Solve the system by the elimination method. 3x - 2y - 7 = 0 5x + y - 3 = 0 To eliminate y, the LCM is 2. Which of the following is the resulting equations? 3x - 2y - 7 = 0 5x + y - 3 = 0 3x - 2y - 7 = 0 -10x - 2y + 6 = 0 3x - 2y - 7 = 0 10x + 2y - 6 = 0
Accepted Solution
A:
Next time, please share your system of linear equations by typing only one equation per line:
3x - 2y - 7 = 0 5x + y - 3 = 0 NO
3x - 2y - 7 = 0 5x + y - 3 = 0 YES
Mult. the 2nd equation by 2 so as to obtain 2y, which will be cancelled out by - 2y in the first equation:
3x - 2y - 7 = 0 2(5x + y - 3 = 0)
Then:
3x - 2y - 7 = 0 10x +2y - 6 = 0 ---------------------- 13x - 13 = 0, so that x = 1. Find y by subbing 1 for x in either of the 2 given equations.