Let x,x+2,x+4,x+6 be 4 consecutive no then,sum of first 3 no=4x+12According to condition,20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd5(x+6)-20=4+(sum of first 3 no)5(x+6)-20=4+(4x+12)5(x+6)-20=4x+165x+30-20=4x+165x+10=4x+165x-4x=16-10x=6So,1st no=x=62nd no=x+2=83rd no=x+4=6+4=104th no=x+6=6+6=12