Mr. Brown has taken out a loan of value $1,000 with a 5% APR. He has been paying off the loan at a constant rate of r = $150/year. Set up a linear ODE for the balance of the loan P(t) as a function of time t in years. [If you're having trouble getting started, please see Example 2 from
Accepted Solution
A:
Answer:[tex]\frac{dp}{dt}[/tex] = 0.05P - 150Step-by-step explanation:Let P(t) be the balance of the loan at time t years,Let P(t) will satisfy [tex]\frac{dp}{dt}=rP-R[/tex]where r = annual interest rate R = per year payment rate R = $150/year r = [tex]\frac{5}{100}[/tex] = 0.05 [tex]\frac{5}{100}[/tex]Now we have the following picture,Interest Balance Payment5% ⇒ P(t) ⇒ $150/year(0.05)Therefore, a linear ODE satisfied by P(t) is given by[tex]\frac{dp}{dt}[/tex] = 0.05P - 150